x^2-9x+4.5^2=0

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Solution for x^2-9x+4.5^2=0 equation: 



x^2-9x+4.5^2=0

We add all the numbers together, and all the variables

x^2-9x+20.25=0

a = 1; b = -9; c = +20.25;
Δ = b2-4ac
Δ = -92-4·1·20.25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{9}{2}=4+1/2$

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